Volume Consumed Re: <VV> Engine Question - Some Corvair
FrankCB at aol.com
FrankCB at aol.com
Tue Dec 25 17:41:38 EST 2007
Bob,
Since it take 2 revolutions of the engine to go throufh one cycle, the
correct answer to how much VOLUME of air-fuel mixture is consumed is:
displacement x RPM x 0.5
So a 164 cu.in engine at 6000 rpm consumes 164 x 6000 rpm x 0.5 =
492,000 cu.in. of mix per minute. But this doesn't tell you how much HP is
produced since HP depends on how much WEIGHT of air/fuel mix is consumed. So you
also need to know the temp. and pressure of the mix entering the combustion
chamber to calculate the WEIGHT of the flow. And anything that increases the
pressure and/or decreases the temp. of the mix will increase the HP since it
will increase the WEIGHT flow for a certain displacement at a certain rpm
See how easy it is?<GGGGG>
Frank Burkhard
In a message dated 12/24/2007 10:37:25 PM Eastern Standard Time,
bgilbert at redshift.bc.ca writes:
Today we had a lively discussion on the volume of fuel/air mixture consumed
by an engine per crankshaft revolution.
We are talking normally aspirated 6 cylinder and V8 4 cycle gasoline
engines.
Is it engine displacement X .5 X RPM, engine displacement X RPM , engine
displacement X 2 X RPM or something else?
Thanks and Merry Christmas!
Bob
**************************************See AOL's top rated recipes
(http://food.aol.com/top-rated-recipes?NCID=aoltop00030000000004)
More information about the VirtualVairs
mailing list